Evaluate ∫0−4(1−2x)dx
...Evaluate ∫0−4(1−2x)dx
-16
-20
20
10
Correct answer is C
∫0−4(1−2x)dx=[x−x2]0−4=(0−0+C)−(−4(−4)2+C)=C−(−4−16+C)=C−(−20+C)=C+20−C=20
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