2.17V
1.49V
1.09V
0.34V
Correct answer is D
The stopping potential is the potential required to stop the most energetic photo-emitted electron. From the relation e Vs = K.E,(max) where e is the electron charge, and Vs is the stopping potential => e x Vs = 0.34eV
∴ Vs = (0.34eV) / e = 0.34V
∴ stopping potential = 0.34V
The wave phenomenon demonstrated in the diagram above is? ...