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Evaluate $\int_{1}^{3}(x^2 - 1)dx$
...

Evaluate $\int_{1}^{3}(x^2 - 1)dx$

A.

$\frac{2}{3}$

B.

$-\frac{2}{3}$

C.

$-6\frac{2}{3}$

D.

$6\frac{2}{3}$

View answer & explanation

Correct answer is D

$\int_{1}^{3}(x^2 - 1)dx = \left[\frac{1}{3}x^2 - x\right] ^{3}_{1}\\ =(9-3)-(\frac{1}{3}-1)\\ =6-\left(-\frac{2}{3}\right)\\ =6+\frac{2}{3}=6\frac{2}{3}$

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