The graph of the function y = x\(^2\) + 4 and a straight ...
The graph of the function y = x\(^2\) + 4 and a straight line PQ are drawn to solve the equation x\(^2\) - 3x + 2 = 0. What is the equation of PQ?
y = 3x - 2
y = 3x + 2
y = 3x - 4
y = 3x + 4
Correct answer is B
x\(^2\) + 4 = x\(^2\) - 3x + 2
3x + 2 = y
Solve the inequalities -3(x - 2) < -2(x + 3) ...
Make q the subject of the formula in the equation \(\frac{mn}{a^2} - \frac{pq}{b^2} = 1\)...
Find the value of x such that the expression \(\frac{1}{x}+\frac{4}{3x}-\frac{5}{6x}+1\) equals...
Make s the subject of the relation: P = S + \(\frac{sm^2}{nr}\)...
Factorize r2 - r(2p + q) + 2pq ...
If b3 = a-2 and c\(\frac{1}{3}\) = a\(\frac{1}{2}\)b, express c in terms of a...
If (x - a) is a factor pf bx - ax + x2, find the other factor....