A current of 0.5 A flowing 3h Deposits 2g of metal during...
A current of 0.5 A flowing 3h Deposits 2g of metal during electrolysis. The quantity of the same metal that would be deposited by the currents of 1.5A flowing in 1h is
2g
6g
10g
18g
Correct answer is A
From Faradays Law, mass deposited during electrolysis is given by
M = ItZ
=> Z = M/(It)
| = | __2 |
| 0.5x3x60x60 |