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A current of 0.5 A flowing 3h Deposits 2g of metal during...

A current of 0.5 A flowing 3h Deposits 2g of metal during electrolysis. The quantity of the same metal that would be deposited by the currents of 1.5A flowing in 1h is

A.

2g

B.

6g

C.

10g

D.

18g

Correct answer is A

From Faradays Law, mass deposited during electrolysis is given by
M = ItZ
=> Z = M/(It)

= __2
0.5x3x60x60

For a current of 1.5A flowing for 1h, the mass M, deposited is given by
M= ZiT
= 2 / (0.5x3x60x60) x 0.5x1x60x60 / 1
= 2.0g
M = 2.0g