10.0Ω
7.5Ω
5.0Ω
2.5Ω
Correct answer is D
From Ohms Law, E = I(R +X) => E = I1(R1 + X) again, E = I2(R2 + X) => I1(R1 + X) = I2(R2 + X) ∴ 5(8 + X) = 7(5 + X) 40 + 5X = 35 + 7X 7X - 5X = 40 - 35 2X = 5 X = 5/2 = 2.5Ω
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