Home / Aptitude Tests / Physics / A coin place below a...

A coin place below a rectangular glass block of thickness...

A coin place below a rectangular glass block of thickness 9cm and refractive index 1.5 is viewed vertically above the block. The apparent displacement of the coin is

A.

3 cm

B.

5 cm

C.

6 cm

D.

8 cm

Correct answer is A

Real depth = thickness of the glass block = 9cm.
Refractive index of the glass material = 1.5
But Refractive index = Real depth/Apparent depth
=> 1.5 = 9/Apparent depth
therefore Apparent depth = 9/1.5 = 6cm.
therefore Apparent displacement of the Coin = 9.6
= 3cm