A capacitor of 20 x 10^-12F and an inductor are joined in series. The value of the inductance that will give the circuit a resonance frequency of 200kHz is

I/16 H

I/8 H

I/64 H

I/32 H

Correct answer is D

Resonant, frequency in an a.c. circuit is given by F = I/2π√LC
therefore 200 * 10³ = I/2 * π√l * 20 * 10^-12
therefore (2.0 * 10⁵)² = I/4 * π² * L * 20 * 10^-12
THEREFORE L = I/4.0 * 10¹⁰ * 4 * 10 * 20 * 10^-12
(if π² = 10)
= I/16 * 10¹¹ * 2.0 * 10^-11
Therefore L = I/32 H

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