3 Ω
2 Ω
1 Ω
6 Ω
Correct answer is A
1 = V/R = E/R+r , if r = 2Ω V = 3/5 E => 3E/5R = E/R+2 i.e 3E(R+2) = 5RE 3RE + 6E = 5RE i.e 3R + 6 = 5R 6 = 5R - 3R => 2r = 6 i.e R = 6/2 = 3Ω
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