A catapult used to hold a stone of mass 500g is extended ...
A catapult used to hold a stone of mass 500g is extended by 20cm with an applied force F. If the stone leaves with a velocity of 40m/s, the value of F is
4.0 x 102N
2.0 x 103N
4.0 x 103N
4.0 x 104N
Correct answer is C
Work done = kinetic energy of the stone
12Fe=12mv2
Given m = 500g = 0.5kg; v = 40m/s ; e = 20cm = 0.2m
F=mv2e
= 0.5×(40)20.2
= 4.0 × 103 N
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