A galvanometer has a resistance of 5Ω. By using a s...
A galvanometer has a resistance of 5Ω. By using a shunt wire of resistance 0.05Ω, the galvanometer could be converted to an ammeter capable of reading 2Amp. What is the current through the galvanometer?
2mA
10mA
20mA
25mA
Correct answer is C
Shunt resistance is usually given as
R = igrg/(I - ig)
Where R = 0.05Ω
rg = 5Ω
I = 2M
∴ ig = IR/(rg + R)
= (2 x 0.05)/(5 + 0.05)
= 0.10/5.05
= 0.0198A
= 19.8mA
= 20mA
The diagram above illustrates a mode of vibration of a wire of length 125 cm. The speed of the ...
The electricity meters in houses measure energy unit consumed in ...
When blue and green colours of light are mixed, the resultant colour is ...
Two inductors of inductance 5 mll and 15 mll are connected in series and a current of 5A flows ...
One valid assumption of the kinetic theory of gasses is the ...
Plane waves through a narrow gap emerge as circular waves. This phenomenon is known as ...
In the diagram above, the time taken to trace a wave between P and Q is? ...