Edet's age was equal to square of some number last year and the following year it would be cube of a number. If again Edet's age has to be equal to the cube of some number, then for how long will he have to wait?
10 years
38 years
39 years
64 years
Correct answer is B
Clearly, we have to first find two numbers whose difference is 2 and of which the smaller one is a perfect square and the bigger one a perfect cube.
Such numbers are 25 and 27.
Thus, Edet is now 26 years old. Since the next perfect cube after 27 is 64,
so required time period = (64 - 26) years = 38 years.