An LED has a rating of 2 V and 10 mA. It is used along with 6V battery. The range of series resistance is
0 to 200 Ω
200 - 400 Ω
200 Ω and above
400 Ω and above
Correct answer is D
R = (6-2/10x10-3) = 400Ω.
R must be at least 400Ω so that current in LED does not exceed 10 mA.