2.15 mol dm-3
0.74 mol dm-3
0.60 mol dm-3
0.57 mol dm-3
Correct answer is B
Molar mass of Na2SO4 = 2(Na) + S + 4(O) = 2(23.0 g/mol) + 32.1 g/mol + 4(16.0 g/mol) = 46.0 g/mol + 32.1 g/mol + 64.0 g/mol = 142.1 g/mol
Now, we can calculate the number of moles of Na2SO4 in the solution:
Number of moles = Mass of the salt / Molar mass
Number of moles = 10.5 g / 142.1 g/mol ≈ 0.0739 mol
Next, we need to find the volume of the saturated solution, given as 100 cm³, and convert it to liters:
Volume of solution = 100 cm³ = 100 cm³ / 1000 cm³/dm³ = 0.1 dm³
Finally, we can calculate the solubility in mol/dm³:
Solubility = Number of moles / Volume of solution
Solubility = 0.0739 mol / 0.1 dm³ ≈ 0.739 mol/dm³
Rounded to two decimal places, the solubility of sodium tetraoxosulphate (VI) at 30°C is approximately 0.74 mol/dm³.
Therefore, the correct option is:
0.74 mol dm-3.
Solubility = 10.5 g / 100 cm3 * 142 g/mol = 0.739 mol/dm3
What is the atomic number of Cesium? ...
A form of carbon used for absorbing poisonous gases and purification of noble gases is ...
Z in diagram above represents...
The nucleus of an atom contains ...
Which of the following ions requires the largest quantity of electricity for dischar...
The best way to distinguish between Na2CO3and NaHCO2 is by....
When concentrated H2 SO 4 is added to NaCI (s), the gas evolved...