If gas A has a molar mass of 32 g/mol and gas B has a mol...
If gas A has a molar mass of 32 g/mol and gas B has a molar mass of 64 g/mol, what is the ratio of their diffusion rates?
2:1
1:2
1:1
1:4
Correct answer is A
According to Graham's law of diffusion, the ratio of the diffusion rates of two gases is the inverse of the square root of the ratio of their molar masses. Therefore:
Rate of A / Rate of B = √(Molar mass of B / Molar mass of A)
Rate of A / Rate of B = √(64 g/mol / 32 g/mol) = √2 = 1.41
So, the ratio of their diffusion rates is approximately 2:1.
What is the chemical symbol for Lawrencium? ...
CuO(s) + H2(g) ↔ Cu(s) + H2O(g) What is the effect of increasing the pressure on the...
What is the chemical symbol for Rubidium? ...
Which of the following equations represents an oxidizing action of sulphur dioxide? ...
Ionization energy increases across the period in the periodic table because ...