If 60 g of M combines with 24 g of oxygen, what would the empirical formula of the oxide be?

( molar mass of M = 120, O = 16)

MO\(_{2}\)

MO\(_{3}\)

MO\(_{4}\)

Correct answer is C

Data obtained from the question
M = 60 g
O = 24 g
Empirical formula =?
How to determine the empirical formula
Divide by their molar mass
M = 60÷120 = 0.5
O = 24 ÷16 = 1.5
Divide by the smallest
M = 0.5÷0.5 = 1
O = 1.5 ÷0.5 = 3
Thus, the empirical formula of the oxide is MO₃

See all Chemistry questions & answers

See more WAEC questions & answers

If 60 g of M combines with 24 g of oxygen, what would the empirical formula of the oxide be?

( molar mass of M = 120, O = 16)

Similar Questions

Aptitude Tests

If 60 g of M combines with 24 g of oxygen, what would the empirical formula of the oxide be? ( molar mass of M = 120, O = 16)

Similar Questions

Aptitude Tests

If 60 g of M combines with 24 g of oxygen, what would the empirical formula of the oxide be?

( molar mass of M = 120, O = 16)