An organic compound contains 69% carbon, 15.3% hydrogen and 30.7% oxygen. Calculate the the empirical formula [C=12, H = 1, O = 16]
C\(_4\)H\(_12\)O
C\(_3\)H\(_9\)O
C\(_4\)H\(_9\)O
C\(_3\)H\(_8\)O
Correct answer is D
C \(\frac{69}{12}\) H \(\frac{15.3}{1}\) O \(\frac{30.7}{16}\)
C = 5.75, H = 15.3, O = 1.92
C \(\frac{5.75}{1,92}\) H \(\frac{15.3}{1.92}\) O \(\frac{1.92}{1.92}\)
C\(_3\)H\(_8\)O