What quantity of electricity will liberate 0.125 mole of oxygen molecules during the electrolysis of dilute sodium chloride solution?
24,125 C
48,250 C
72,375 C
96,500 C
Correct answer is B
4OH ⇒ 2H\(_2\)O + O\(_2\) + 4e-
From the equation:
1 mole of Oxygen requires 4e
i.e 1 mole of Oxygen requires 4F,
where 1F = 96,500 C
[ 4 X 96,500 X 0.125 ] ÷ 1
= 48,250 C