If the quantity of oxygen occupying 2.76L container at a ...
If the quantity of oxygen occupying 2.76L container at a pressure of 0.825 atm and 300k is reduced by one-half, what is the pressure exerted by the remaining gas?
1.650atm
0.825atm
0.413atm
0.275atm
Correct answer is A
Using the combined gas law formula,
Given that P1 = 0.825, V1 = 2.76 L, V2 = 1.38 L, P2 = ?
And T1 = T2; we would have P2 = [ P1 X V1 ] ÷ V2
: [0.825 X 2.76] ÷ 1.38
= 1.650atm
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