8g of CH\(_4\) occupies 11.2 at S.T.P. What volume would 22g of CH\(_3\)CH\(_2\)CH\(_3\) occupy under the same condition?

A.

3.7dm\(^3\)

B.

11.2dm\(^3\)

C.

22.4dm\(^3\)

D.

33dm\(^3\)

Correct answer is B

Molar mass of methane = 16g/mol

At S.T.P.       its 8g occupies 11.2

                    so 16g occupies 22.4 dm\(^3\)

 

Molar mass of propane = 44g/mol\(^-1\) occupies 22.4dm\(^3\) at S.T.P

                      so 22g will occupy 11.2dm\(^3\)