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The electronic configuration of element Z is 1s $^2$ 2s\(^2...

The electronic configuration of element Z is 1s $^2$ 2s $^2$ 2p $^6$ 3s $^2$ 3p $^1$ . What is the formula of the compound formed between Z and tetraoxosulphate (VI) ion.

A.

Z $_3$ (SO $_4$ ) $_2$

B.

ZSO $_4$

C.

Z $_2$ SO $_4$

D.

Z $_2$ (SO $_4$ ) $_3$

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Correct answer is D

Z = 1s $^2$ 2s $^2$ 2p $^6$ 3s $^2$ 3p $^1$

$\therefore$ We have Z $^{3+}$ and SO $_4 ^{2-}$

The reaction : Z $^{3+}$ + SO $_4 ^{2-}$ $\to$ Z $_2$ (SO $_4$ ) $_3$ .

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