Consider the following reaction equation: \(2NO_{(g)} + O_{{2}{(g)}} \to 2NO_{{2}{(g)}}\). What is the change in the oxidation number of nitrogen?

A.

+2 to 0

B.

+2 to -2

C.

+2 to +4

D.

+4 to +2

View answer & explanation

Correct answer is C

In NO, the oxidation number for nitrogen is N - 2 = 0

⇒ N = +2

In \(NO_{2}\), we have N - (2x2) =0

N - 4 =0

N =+4

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