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If 0.2g of a salt is required to saturate 200 $cm^{3}$ of w...

If 0.2g of a salt is required to saturate 200 $cm^{3}$ of water at room temperature, what is the solubility of the salt?

A.

0.2 $gdm^{-3}$

B.

1.0 $gdm^{-3}$

C.

2.0 $gdm^{-3}$

D.

5.0 $gdm^{-3}$

View answer & explanation

Correct answer is B

Solubility in $gdm^{-3}$ = $\frac{mass of salt in gram}{volume of liquid in dm^{3}}$

200 $cm^{3}$ = $\frac{200}{1000} dm^{3} = 0.2dm^{3}$

Solubility = $\frac{0.2g}{0.2dm^{3}}$

= 1.0 $gdm^{-3}$

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