3H $_{2(g)}$ + N $_{2(g)}$ ⇔ 2NH $_{3(g)}$ ; H= -ve
In the reaction above, lowering of temperature will

have no effect on the equilibrium position

increase the rate of both the forward and reverse reactions equally

favour the forward reaction

favour the reverse reaction

Correct answer is C

N $_{2(g)}$ + 3H $_{2(g)}$ ⇔ 2NH $_{3(g)}$ In the Haber process, the forward reaction is exothermic and the backward reaction is endothermic. If the temperature is decreased, the yield from the exothermic direction is increased i.e. the forward reaction is increased.

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