Calculate the pH of 0.05 moldm\(^{-3}\) H\(_2\)SO\(_4\)
1.30
1.12
1.00
0.30
Correct answer is C
Recall from pH formula pH = -Log [H+]
H2SO4 → 2H+ + SO42-
2H+ → 2 X0.05 = 0.1
pH= -Log [0.1] = 1
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