Calculate the amount in moles of silver deposited when 9650C of electricty is passed through a solution of silver salt [= 96500 Cmol^-1]

0.05

10.80

10.00

0.10

Correct answer is D

m = $\frac{Mm \times Q}{96500n }$

where Q = IT

M = Mm × $\frac{Q}{96500n}$

where m = mass

Mm = Molar mass

Q = Quantity of electricity

n = number of change= +1

$\frac{M}{Mm}$ = mole = $\frac{mass}{Molarmass}$

$\frac{M}{Mm}$ = $\frac{Q}{96500n}$

= $\frac{9650}{96500n}$ × 1

= $\frac{1}{10}$ = 0.1mol

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Calculate the amount in moles of silver deposited when 9650C of electricty is passed through a solution of silver salt [= 96500 Cmol^-1]