400k
480k
550k
600k
Correct answer is D
At constant pressure connotes Charle's law \(\frac{V_1}{T_1}\) = \(\frac{V_2}{T_2}\) \(\frac{2dm^3}{300k}\) = 2 x \(\frac{2dm^3}{T_2}\) T2= 600k
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