The number of oxygen molecules present in 16.0g of the gas is ______?
[Avogadro's number = 6.02 x 1023]

A.

6.02 x 1022

B.

6.02 x 1023

C.

3.01 x 1023

D.

1.51 x 1023

View answer & explanation

Correct answer is C

1 mole = Molar mass of gas = Avogadros number
32g of O2 = 6.02 x 1023
16g of O2 = x
x = \(\frac{16 \times 6.02 \times 10^23}{32}\) = 3.01 x 1023

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