How many moles of oxygen would contain 1.204 x 1024 molecules? [Avogadro's constant (NA) = 6.02 x 10.... Question 36557

How many moles of oxygen would contain 1.204 x 10²⁴ molecules?
[Avogadro's constant (NA) = 6.02 x 10²³]

Correct answer is B

6.02 x 10²³ molecules is 1mole
1.204 x 10²⁴ molecules will be......

\(\frac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)

\(\frac{1.204 \times 10}{6.02}\) = \(\frac{12.04}{6.02}\) = 2moles