Calculate the volume in cm³ of oxygen evolved at s.t.p when a current of 5A is passed through acidified water for 193s?
[F = 96500 C mol¹. Molar volume of a gas at s.t.p = 22.4dm³]

0.056dm³

0.224dm³

224.000dm³

56.000dm³

Correct answer is A

Q = 193 x 5 = 965C
40H \(\mapsto\) 2H₂O + O₂ + 4e
4 x 96500C = 22.4dm³
965C = x

x = \(\frac{22.4 \times 965}{4 \times 96500}\)
= 0.056dm³

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Calculate the volume in cm3 of oxygen evolved at s.t.p when a current of 5A is passed through acidified water for 193s? [F = 96500 C mol1. Molar volume of a gas at s.t.p = 22.4dm3]