Given that the molecular mass of iron is 56 and that of oxygen is 16, how many moles of iron(iii)oxide will be contained in 1kg of the compound?
25.0 moles
12.5 moles
6.25 moles
3.125 moles
0.625 moles
Correct answer is C
Fe2O3 = 56 x 2 + 48 = 160 = 1 moles
1000gm will contain \(\frac{1000}{160}\) = 6.25 moles