14
13
12
11
Correct answer is D
[H+][OH−] = 10 − 4 [H+] =10 − 14 ÷ [OH+] =10 −14 ÷ (1 × 10 − 3) = 10 − 11 pH = − log10[H+ ] = − log10[10 − 11] = − 1 × −11 log10[10 − 11] = 1 = − 1 × 11 × 1 = − 11
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