The number of sulphur atoms in 3.20g of SO\(_{2(g)}\) is [O = 16.0;S = 32.0; Avogadro constant = 6.02 x 10\(^{23}\)]

A.

3.01 x 1022

B.

6.02 x 1022

C.

6.02 x1023

D.

1.20 x 1024

View answer & explanation

Correct answer is A

32g of sulphur = 64g / 6.02 x 10\(^{23}\) atoms of SO\(_2\)

xg of sulphur = 3.2g of SO\(_2\) 

: 1.6g of sulphur is present in 3.2g / 3.01 x 10\(^{23}\) atoms of SO\(_2\)  

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