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The number of sulphur atoms in 3.20g of SO $_{2(g)}$ is [O ...

The number of sulphur atoms in 3.20g of SO $_{2(g)}$ is [O = 16.0;S = 32.0; Avogadro constant = 6.02 x 10 $^{23}$ ]

A.

3.01 x 10²²

B.

6.02 x 10²²

C.

6.02 x10²³

D.

1.20 x 10²⁴

View answer & explanation

Correct answer is A

32g of sulphur = 64g / 6.02 x 10 $^{23}$ atoms of SO $_2$

xg of sulphur = 3.2g of SO $_2$

: 1.6g of sulphur is present in 3.2g / 3.01 x 10 $^{23}$ atoms of SO $_2$

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