What is the oxidation number of chromium in K2CrO4?

A.

+1

B.

+2

C.

+4

D.

+6

View answer & explanation

Correct answer is D

K2CrO4 (O.N of K) X 2 + O.N of Cr + (O.N of oxygen) X 4 = 0
1 X 2 + X + -2 X 4 = 0
2 + x + -8 = 0
2 + x - 8 = 0
x = 8 - 2 = + 6

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