2NaNO3 → 2NaNO2 + O2. From the equation above, what ...
2NaNO3 → 2NaNO2 + O2. From the equation above, what is the volume of oxygen produced at s.t.p. when 8.5g of 2NaNO3 is heated until no further gas is evolved? (2NaNO3 = 85, molar volume of gases at s.t.p. = 22.4dm3)
1.12dm3
2.24dm3
4.48dm3
11.2dm3
22.4dm3
Correct answer is A
85g of 2NaNO3 will liberated 22.4dm3
8.5g = xdm3
cross multiply: x = [8.5 * 22.4] / 85
x = 2.24dm3
: 8.5g of 2NaNO3 = 2.24dm3
where 2moles of NaNO3 liberates 1mole of O2
2.24dm3 of NaNO3 liberates 1.12dm3 of O2
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