The above diagram gives the potential energy profile of the catalyst and uncatalysed reactions of X(g) + Y(g) → XY(g). Deduce the respective activation energies in KJ of the catalysed and uncatalysed reverse reactions: XY(g) → X(g) + Y(g)
A.
300, 500
B.
500, 300
C.
-300, -500
D.
-500, -300
Correct answer is C
The uncatalysed reverse reaction = 100 - 400 = -300 The calalysed reverse reaction = 100 - 600 = - 500