10 g
12 g
14 g
16 g
18 g
Correct answer is D
At 80°C, we have \(1000cm^{3} = 0.4mol/cm^{3}\)
40°C = \(0.3mol/cm^{3}\)
hence, the loss in concentration = \(0.1mol/cm^{3}\)
= \(0.1 \times 160 = 16g\)
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