2.0 cm 3
5.0 cm 3
6.8 cm 3
8.3 cm 3
10.4 cm 3
Correct answer is A
\(\frac{C_AV_A}{C_bV_b} = \frac{1}{2}\) \(frac{0.5 \times V_A}{0.1 \times 20} = \frac{1}{2}\) \(V_A = \frac{0.1 \times 20}{2 \times 0.5} = \frac{1.0}{0.5)\) = 2cm2
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