+2081 Jmol-1
-2081 Jmol-1
-649 Jmol-1
+649 Jmol-1
Correct answer is A
∆G = ∆H - T∆S
-899 = ∆H - 2980
∆H = -899 + 2980 = + 2081 Jmol-1
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