16.55g of lead (ll) trioxonitrate (V) was dissolved in 10...
16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC, calculate the solubility of the solute in moldm-3
[Pb = 207, N = 14, O = 16]
0.05 g
2.00 g
1.00 g
0.50g
Correct answer is D
molar mass of pb (N0 3) 2 = 331
Mole = \(\frac{16.55}{331}\)= 0.05 mole
∴0.05mole pb (No3)2 dissolved in 1000g H2O x = \(\frac{0.05\times1000}{100}\)= 0.5 mole /dm 3
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