16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC, calculate the solubility of the solute in moldm-3

[Pb = 207, N = 14, O = 16]

0.05 g

2.00 g

1.00 g

0.50g

Correct answer is D

molar mass of pb (N0 3) 2 = 331
Mole = $\frac{16.55}{331}$ = 0.05 mole
∴0.05mole pb (No3)2 dissolved in 1000g H2O x = $\frac{0.05\times1000}{100}$ = 0.5 mole /dm 3

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16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC, calculate the solubility of the solute in moldm-3

[Pb = 207, N = 14, O = 16]

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16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC, calculate the solubility of the solute in moldm-3 [Pb = 207, N = 14, O = 16]

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Aptitude Tests

16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC, calculate the solubility of the solute in moldm-3

[Pb = 207, N = 14, O = 16]