1.7g
3.4g
6.8g
13. 6 g
Correct answer is B
From Faraday;s second law of electrolysis
\(\frac{\text{Mass of silver deposited}}{\text{Mass of copper deposited}}\) = \(\frac{\text{Equivalent mass of silver}}{\text{Equivalent mass of copper}}\)
\(\frac{\text{Mass of silver deposited}}{1.0g}\) = \(\frac{108}{63.5}\)
= 31.75g
Copper is devalent = Cu2+
Mass of silver deposited = \(\frac{108g}{31.75g}\)
= 3.30g