One mole of propane is mixed with five moles of oxygen. The mixture is ignited and the propane burns completely. What is the volume of the products at s.t.p?

(G.M.V = 22.4 dm³ mol^-1)

112.0 dm³

67.2 dm³

56.0 dm³

44.8 dm³

Correct answer is B

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
When the mixture is ignited CO₂ is collected as product. From the equation 33 moles of CO₂ is produced which equals 3 x 2.4 dm³ = 67.2 dm³ at S.T.P

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One mole of propane is mixed with five moles of oxygen. The mixture is ignited and the propane burns completely. What is the volume of the products at s.t.p?

(G.M.V = 22.4 dm³ mol^-1)

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One mole of propane is mixed with five moles of oxygen. The mixture is ignited and the propane burns completely. What is the volume of the products at s.t.p? (G.M.V = 22.4 dm3 mol-1)

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Aptitude Tests

One mole of propane is mixed with five moles of oxygen. The mixture is ignited and the propane burns completely. What is the volume of the products at s.t.p?

(G.M.V = 22.4 dm³ mol^-1)