20 cm³ of 1.0 molar NH₄OH solution when neutralized with 20.05cm³ of 0.1 molar HCl liberated -102 joules of heat. Calculate the heat of neutralization of NH₄OH?

-51.O KJ mol^-

+57.3 KJ mol^-

+57.O KJ mol^-

+51.0 KJ mol^-

Correct answer is A

NH₄OH = 20cm of 0.1 m
NH₄ + HCl → NH₄Cl = H₂O
Heat of Neutralization of NH₄OH
= \(\frac{-102}{2}\) = -51.0 KJ mole^-1

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