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A given amount of gas occupies 10.0 dm3 at 4atm and 273&d...

A given amount of gas occupies 10.0 dm3 at 4atm and 273°C. The number of moles of the gas present is?
(Molar volume of a gas at s.t.p. = 22.4 dm3)

A.

0.89 mol

B.

1.90 mol

C.

3.80 mol

D.

5.70 mol

Correct answer is A

V1 = 10dm3, V2 = ?, P1 = 4atm =  4 x 760 = 3040mmHg, P2 = 760mmHg T1 = 273ºc = 273 + 273 = 546K, T2 = 273K

Using the general gas law = P1V1T1=P2V2T2

V2=P1V1T2P2T1

V2=3040×10×273760×546

V2=20dm3

1mole of a gas = 22.4dm3

  x                     = 20.0dm3

= 0.89mol.