A given amount of gas occupies 10.0 dm3 at 4atm and 273&d...
A given amount of gas occupies 10.0 dm3 at 4atm and 273°C. The number of moles of the gas present is?
(Molar volume of a gas at s.t.p. = 22.4 dm3)
0.89 mol
1.90 mol
3.80 mol
5.70 mol
Correct answer is A
V1 = 10dm3, V2 = ?, P1 = 4atm = 4 x 760 = 3040mmHg, P2 = 760mmHg T1 = 273ºc = 273 + 273 = 546K, T2 = 273K
Using the general gas law = P1V1T1=P2V2T2
V2=P1V1T2P2T1
V2=3040×10×273760×546
V2=20dm−3
1mole of a gas = 22.4dm3
x = 20.0dm3
= 0.89mol.
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