Given that 15.00 cm³ of H₂
SO₄ was required to completely neutralize 25.00 cm³ of 0.125 mol dm^-3 NaOH, calculate the molar concentration of the acid solution:

0.925 mol dm^-3

0.156mol dm^-3

0.104 mol dm^-3

0.023 mol dm^-3

Correct answer is C

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
(M_aV_a)/(M_BV_B) (1)/(2) (M_A x 15)/(0.125 x25) = 1/2
M_A = 0.104

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Given that 15.00 cm3 of H2 SO4 was required to completely neutralize 25.00 cm3 of 0.125 mol dm-3 NaOH, calculate the molar concentration of the acid solution: