An organic compound containing 40.1% carbon and 6.6% hydrogen has an empirical formula of?
C2H4O2
C2H3O2
CH2O
CH3O
Correct answer is C
Carbon Hydrogen
40.1..........................6.67
(3.342) / (3.342).............(6.67) / (3.342)
1 1.9958
1 Ω 2
CH2O