In two separate experiments, 0.36g and 0.71g of chlorine combined with a metal X to give Y and Z respectively. An analysis showed that Y and Z contain 0.20g and 0.40g of X respectively. The data above represents the law of ?
multiple proportion
conservation of mass
constant composition
reciprocal proportion
Correct answer is C
0.36g of Cl combines with 0.2g of x
1g of Cl will combine with \(\frac{1 \times 0.2}{0.32}\) = 0.56
0.71g of U combines with 0.49g of x
1g of U will combine with \(\frac{1 \times 0.4}{71}\) = 0.56
Ratio 0.56 : 0.56 = 1:1