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An iron ore is known to contain 70.0% Fe2O3<...

An iron ore is known to contain 70.0% Fe2O3. The obtain from 80kg of the ore is?

(Fe = 56, O = 16)

A.

35.0 kg

B.

39.2 kg

C.

70.0 kg

D.

78.4 kg

View answer & explanation

Correct answer is B

2Fe2O3 → 4Fe + 3O2
320g 224g 96g
(70) / (100) x (80) / (1) 56g
if 0.32kg of Fe293 contains 0.224 kg
Then 56kg will contain (56 x 0.224) / (0.32) =39.2 kg

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