From the diagram above, find the amount of solute deposited when 200 cm33 of the solution is cooled from 55°C to 40°C.
A.
0.10 mole
B.
0.20mole
C.
0.01 mole
D.
0.02 mole
Correct answer is B
From the diagram,
55°C = 7 moles; 40°C = 6 moles.
Amount of solute deposited = 7 - 6 = 1 mole.
1000 cm\(^3\) = 1 mole
200 cm\(^3\) = x
x = \(\frac{200 \times 1}{1000}\)
= 0.20 mole.