\(NH_{3(g)} + HCl_{(g)} → NH_4Cl_{(s)}\)
The e...
\(NH_{3(g)} + HCl_{(g)} → NH_4Cl_{(s)}\)
The entropy change in the system above is
positive
zero
negative
indeterminate
Correct answer is C
\(NH_{3(g)} + HCl_{(g)} → NH_4Cl_{(s)}\)
Reactant = 2 moles of gaseous molecules
Product = 1 mole of gaseous molecule
Entropy change = 1 - 2 = -1 (negative)
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